Calculus II - The
beginnings of integration can be recognised in the work of the ancient Greeks
(Euclid, Archimedes ) in finding areas of curved regions and volumes of curved
solids.
The beginnings of differentiation were much later, in the work of the early
17th century on tangents to curves and instantaneous rates of change.
The recognition that these two processes are inverses of each other (the
"Fundamental Theorem of Calculus") and the major initial development of the
theory occurred in the late 17th century, mainly in the work of Newton
(1642-1727) and Leibniz (1646-1716).
All calculus was based on the concept of a limit, a concept which was not
well understood until the 19th century (in the work of Cauchy, Riemann,
Weierstrass and others) and until then the results in the calculus were founded
on an unsound, non- rigorous basis.
(e.g. one intuitive idea was that the gradient of the tangent
to the curve at (x,y) is the gradient of the chord, i.e. when For instance if y = x - and when But when This is briefly the finding of areas (or volumes) of curved regions by
successive approximations using inscribed and exscribed polygons (or polyhedra)
and other shapes whose areas (or volumes) are already known. For example,
finding the area of a circle using approximations by regular polygons with
increasing numbers of sides. A more complicated example by Archimedes follows:
We require the shaded area A enclosed by the spiral and the x-axis.
r This divides the area into n sectors (the ith sector is shown)
Enclose the arc between circular sectors i Let S = For the ith sector we have the proportions:
Now
Also
At this stage the modern argument would be something like:
C and the area c i.e. C Hence (by (1)) C i.e. the area A = so A = Archimedes' argument was:
Either A < If A < This can be done because C Now from (2) : C - a contradiction, so A < A similar argument (leading to I - so we must have A = Since the Greeks did not use algebraic notation, the version above would not
be recognisable by Archimedes, but the argument is his.
This was motivated in the early 17th century by four types of problem :
Then when the arc PP' is sufficiently small he identifies it with the line PQ (lack of rigour again !)
y
He subtracts y
2ay + a
The identification of PP/ with PQ is equivalent to discarding nonlinear terms in a and e
(a
Then, since
Since PM is y, he has calculated MN, and hence located the position of N.
With the state of the calculus reaching this point, the stage was set for Newton and Leibniz to develop it into a form recognisable by students today.
Prequisite:Calculus I

x = 0.
, then
gradient of chord =
=
= 2x +
x
x = 0 this is 2x.
x = 0 the chord does
not exist! )

The Method of Exhaustion
(Euclid c.300 B.C., Archimedes 287-212 B.C. )

Archimedean Spiral
(Polar equation r = a* )
Draw radii with angles in
A.P.:
= a
, r
= 2a
, r
= 3a
, ....etc. Where n
= 2
.
and c
, and a third sector s
with radius 2
a, for all i.

So s
= s
= ........ = s
=
(2
a)
.
s
C
=
c
I
=
i
> 3
I
<
< C
- - - - - - - - - - - - -
- - -(1)
- I
=
(c
- i
) = c
( since c
= i
and i
= 0 )
can
be made as small as we like by taking n large enough,
- I
0 as n
.
and I
as n
.
, where S =
(2
a)2


a
,
A >
or A =
.
,
choose n so that C
-
A <
- A - - - -
- - - - (2)
- A < C
- I
=
c
, which can be made
as small as we like by taking n large enough.
<
and from
(1) : Cn >
.
is false.
> and I
<
) shows A >
is
also false
. Note that Archimedes' argument does not use the limit concept,
and is completely rigorous.

The Beginning of Differerentiation
Early progress on these problems (the first steps in using differentiation) were by Fermat (1601-1665) and Barrow (1630-1677).Example of Barrow's Work
Given a curve and a point P on it, find N on the x-axis so that PN is a tangent to the curve.
In one of his calculations he deals with the curve y . Barrow takes another point P' on the curve, and forms
PRQ and
PMN , which are similar, hence the slope
=
.
= kx (k constant), replaces x by x+e and y by y+a to get
+ 2ay + a
= kx + ke
= kx to get
= ke
here), so he concludes 2ay = ke,
i.e.
=
.
=
=
he has
=
.